a2+2601=3600

Solution for a2+2601=3600 equation:

a2+2601=3600

We move all terms to the left:

a2+2601-(3600)=0

We add all the numbers together, and all the variables

a^2-999=0

a = 1; b = 0; c = -999;
Δ = b2-4ac
Δ = 02-4·1·(-999)
Δ = 3996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3996}=\sqrt{36*111}=\sqrt{36}*\sqrt{111}=6\sqrt{111}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{111}}{2*1}=\frac{0-6\sqrt{111}}{2}
=-\frac{6\sqrt{111}}{2}
=-3\sqrt{111}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{111}}{2*1}=\frac{0+6\sqrt{111}}{2}
=\frac{6\sqrt{111}}{2}
=3\sqrt{111}
$