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a/3=(2/5)a-1
We move all terms to the left:
a/3-((2/5)a-1)=0
Domain of the equation: 5)a-1)!=0We add all the numbers together, and all the variables
a!=0/1
a!=0
a∈R
a/3-((+2/5)a-1)=0
We calculate fractions
5a^2/15a+()/15a=0
We multiply all the terms by the denominator
5a^2+()=0
We add all the numbers together, and all the variables
5a^2=0
a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$a=\frac{-b}{2a}=\frac{0}{10}=0$
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