a-4=(a/2)+3

Solution for a-4=(a/2)+3 equation:

a-4=(a/2)+3

We move all terms to the left:

a-4-((a/2)+3)=0

We add all the numbers together, and all the variables

a-((+a/2)+3)-4=0

We multiply all the terms by the denominator


a*2)+3)-((+a-4*2)+3)=0

We add all the numbers together, and all the variables

a*2)+3)-((a-8)+3)=0

We add all the numbers together, and all the variables

a*2)+3)-((a=0

Wy multiply elements

2a^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{4}=0$