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a-4/7=1/(3a-1)
We move all terms to the left:
a-4/7-(1/(3a-1))=0
Domain of the equation: (3a-1))!=0We calculate fractions
a∈R
a+()/21a+(-12a)/21a=0
We multiply all the terms by the denominator
a*21a+(-12a)+()=0
We add all the numbers together, and all the variables
a*21a+(-12a)=0
Wy multiply elements
21a^2+(-12a)=0
We get rid of parentheses
21a^2-12a=0
a = 21; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·21·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*21}=\frac{0}{42} =0 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*21}=\frac{24}{42} =4/7 $
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