a-4(3a+1)=40

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Solution for a-4(3a+1)=40 equation: 



a-4(3a+1)=40

We move all terms to the left:

a-4(3a+1)-(40)=0

We multiply parentheses

a-12a-4-40=0

We add all the numbers together, and all the variables

-11a-44=0

We move all terms containing a to the left, all other terms to the right

-11a=44

a=44/-11

a=-4

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