a-3+8a=7(a+5)+2(8-2a)

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Solution for a-3+8a=7(a+5)+2(8-2a) equation:



a-3+8a=7(a+5)+2(8-2a)
We move all terms to the left:
a-3+8a-(7(a+5)+2(8-2a))=0
We add all the numbers together, and all the variables
a+8a-(7(a+5)+2(-2a+8))-3=0
We add all the numbers together, and all the variables
9a-(7(a+5)+2(-2a+8))-3=0
We calculate terms in parentheses: -(7(a+5)+2(-2a+8)), so:
7(a+5)+2(-2a+8)
We multiply parentheses
7a-4a+35+16
We add all the numbers together, and all the variables
3a+51
Back to the equation:
-(3a+51)
We get rid of parentheses
9a-3a-51-3=0
We add all the numbers together, and all the variables
6a-54=0
We move all terms containing a to the left, all other terms to the right
6a=54
a=54/6
a=9

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