a-3(4a+1)=41

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Solution for a-3(4a+1)=41 equation:



a-3(4a+1)=41
We move all terms to the left:
a-3(4a+1)-(41)=0
We multiply parentheses
a-12a-3-41=0
We add all the numbers together, and all the variables
-11a-44=0
We move all terms containing a to the left, all other terms to the right
-11a=44
a=44/-11
a=-4

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