a-(2a+1)=8+4(3a+2)

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Solution for a-(2a+1)=8+4(3a+2) equation: 



a-(2a+1)=8+4(3a+2)

We move all terms to the left:

a-(2a+1)-(8+4(3a+2))=0

We get rid of parentheses

a-2a-(8+4(3a+2))-1=0



We calculate terms in parentheses: -(8+4(3a+2)), so:

8+4(3a+2)

determiningTheFunctionDomain
4(3a+2)+8

We multiply parentheses

12a+8+8

We add all the numbers together, and all the variables

12a+16

Back to the equation:

-(12a+16)



We add all the numbers together, and all the variables

-1a-(12a+16)-1=0

We get rid of parentheses

-1a-12a-16-1=0

We add all the numbers together, and all the variables

-13a-17=0

We move all terms containing a to the left, all other terms to the right

-13a=17

a=17/-13

a=-1+4/13

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