a+a+a2+a2=360

Solution for a+a+a2+a2=360 equation:

a+a+a2+a2=360

We move all terms to the left:

a+a+a2+a2-(360)=0

We add all the numbers together, and all the variables

2a^2+2a-360=0

a = 2; b = 2; c = -360;
Δ = b2-4ac
Δ = 22-4·2·(-360)
Δ = 2884
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2884}=\sqrt{4*721}=\sqrt{4}*\sqrt{721}=2\sqrt{721}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{721}}{2*2}=\frac{-2-2\sqrt{721}}{4}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{721}}{2*2}=\frac{-2+2\sqrt{721}}{4}
$