a+5(a-1)=10a-4(a+2)

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Solution for a+5(a-1)=10a-4(a+2) equation: 



a+5(a-1)=10a-4(a+2)

We move all terms to the left:

a+5(a-1)-(10a-4(a+2))=0

We multiply parentheses

a+5a-(10a-4(a+2))-5=0



We calculate terms in parentheses: -(10a-4(a+2)), so:

10a-4(a+2)

We multiply parentheses

10a-4a-8

We add all the numbers together, and all the variables

6a-8

Back to the equation:

-(6a-8)



We add all the numbers together, and all the variables

6a-(6a-8)-5=0

We get rid of parentheses

6a-6a+8-5=0

We add all the numbers together, and all the variables

3!=0

There is no solution for this equation

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