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a+3/3-3a-7/5=10
We move all terms to the left:
a+3/3-3a-7/5-(10)=0
determiningTheFunctionDomain a-3a-10+3/3-7/5=0
We add all the numbers together, and all the variables
-2a-9-7/5=0
We multiply all the terms by the denominator
-2a*5-7-9*5=0
We add all the numbers together, and all the variables
-2a*5-52=0
Wy multiply elements
-10a-52=0
We move all terms containing a to the left, all other terms to the right
-10a=52
a=52/-10
a=-5+1/5
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