a+3-4a=2(a-5)

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Solution for a+3-4a=2(a-5) equation:


Simplifying
a + 3 + -4a = 2(a + -5)

Reorder the terms:
3 + a + -4a = 2(a + -5)

Combine like terms: a + -4a = -3a
3 + -3a = 2(a + -5)

Reorder the terms:
3 + -3a = 2(-5 + a)
3 + -3a = (-5 * 2 + a * 2)
3 + -3a = (-10 + 2a)

Solving
3 + -3a = -10 + 2a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-2a' to each side of the equation.
3 + -3a + -2a = -10 + 2a + -2a

Combine like terms: -3a + -2a = -5a
3 + -5a = -10 + 2a + -2a

Combine like terms: 2a + -2a = 0
3 + -5a = -10 + 0
3 + -5a = -10

Add '-3' to each side of the equation.
3 + -3 + -5a = -10 + -3

Combine like terms: 3 + -3 = 0
0 + -5a = -10 + -3
-5a = -10 + -3

Combine like terms: -10 + -3 = -13
-5a = -13

Divide each side by '-5'.
a = 2.6

Simplifying
a = 2.6

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