a+2(a+2)=3(a+1)-5

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Solution for a+2(a+2)=3(a+1)-5 equation: 


Simplifying
a + 2(a + 2) = 3(a + 1) + -5

Reorder the terms:
a + 2(2 + a) = 3(a + 1) + -5
a + (2 * 2 + a * 2) = 3(a + 1) + -5
a + (4 + 2a) = 3(a + 1) + -5

Reorder the terms:
4 + a + 2a = 3(a + 1) + -5

Combine like terms: a + 2a = 3a
4 + 3a = 3(a + 1) + -5

Reorder the terms:
4 + 3a = 3(1 + a) + -5
4 + 3a = (1 * 3 + a * 3) + -5
4 + 3a = (3 + 3a) + -5

Reorder the terms:
4 + 3a = 3 + -5 + 3a

Combine like terms: 3 + -5 = -2
4 + 3a = -2 + 3a

Add '-3a' to each side of the equation.
4 + 3a + -3a = -2 + 3a + -3a

Combine like terms: 3a + -3a = 0
4 + 0 = -2 + 3a + -3a
4 = -2 + 3a + -3a

Combine like terms: 3a + -3a = 0
4 = -2 + 0
4 = -2

Solving
4 = -2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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