a+(d+12)=(d+12)+a

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Solution for a+(d+12)=(d+12)+a equation:


Simplifying
a + (d + 12) = (d + 12) + a

Reorder the terms:
a + (12 + d) = (d + 12) + a

Remove parenthesis around (12 + d)
a + 12 + d = (d + 12) + a

Reorder the terms:
12 + a + d = (d + 12) + a

Reorder the terms:
12 + a + d = (12 + d) + a

Remove parenthesis around (12 + d)
12 + a + d = 12 + d + a

Reorder the terms:
12 + a + d = 12 + a + d

Add '-12' to each side of the equation.
12 + a + -12 + d = 12 + a + -12 + d

Reorder the terms:
12 + -12 + a + d = 12 + a + -12 + d

Combine like terms: 12 + -12 = 0
0 + a + d = 12 + a + -12 + d
a + d = 12 + a + -12 + d

Reorder the terms:
a + d = 12 + -12 + a + d

Combine like terms: 12 + -12 = 0
a + d = 0 + a + d
a + d = a + d

Add '-1a' to each side of the equation.
a + -1a + d = a + -1a + d

Combine like terms: a + -1a = 0
0 + d = a + -1a + d
d = a + -1a + d

Combine like terms: a + -1a = 0
d = 0 + d
d = d

Add '-1d' to each side of the equation.
d + -1d = d + -1d

Combine like terms: d + -1d = 0
0 = d + -1d

Combine like terms: d + -1d = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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