a+(a+3)+(b*3)=2

Solution for a+(a+3)+(b*3)=2 equation:

Simplifying
a + (a + 3) + (b * 3) = 2

Reorder the terms:
a + (3 + a) + (b * 3) = 2

Remove parenthesis around (3 + a)
a + 3 + a + (b * 3) = 2

Reorder the terms for easier multiplication:
a + 3 + a + (3b) = 2

Reorder the terms:
3 + a + a + (3b) = 2

Combine like terms: a + a = 2a
3 + 2a + (3b) = 2

Solving
3 + 2a + (3b) = 2

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + 2a + -3 + (3b) = 2 + -3

Reorder the terms:
3 + -3 + 2a + (3b) = 2 + -3

Combine like terms: 3 + -3 = 0
0 + 2a + (3b) = 2 + -3
2a + (3b) = 2 + -3

Combine like terms: 2 + -3 = -1
2a + (3b) = -1

Add '(-3b)' to each side of the equation.
2a + (3b) + (-3b) = -1 + (-3b)

Combine like terms: (3b) + (-3b) = 0
2a + 0 = -1 + (-3b)
2a = -1 + (-3b)

Divide each side by '2'.
a = -0.5 + (-1.5b)

Simplifying
a = -0.5 + (-1.5b)