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a*6a=500
We move all terms to the left:
a*6a-(500)=0
Wy multiply elements
6a^2-500=0
a = 6; b = 0; c = -500;
Δ = b2-4ac
Δ = 02-4·6·(-500)
Δ = 12000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12000}=\sqrt{400*30}=\sqrt{400}*\sqrt{30}=20\sqrt{30}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{30}}{2*6}=\frac{0-20\sqrt{30}}{12} =-\frac{20\sqrt{30}}{12} =-\frac{5\sqrt{30}}{3} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{30}}{2*6}=\frac{0+20\sqrt{30}}{12} =\frac{20\sqrt{30}}{12} =\frac{5\sqrt{30}}{3} $
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