a(b-3)+s(b-3)=

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Solution for a(b-3)+s(b-3)= equation:


Simplifying
a(b + -3) + s(b + -3) = 0

Reorder the terms:
a(-3 + b) + s(b + -3) = 0
(-3 * a + b * a) + s(b + -3) = 0
(-3a + ab) + s(b + -3) = 0

Reorder the terms:
-3a + ab + s(-3 + b) = 0
-3a + ab + (-3 * s + b * s) = 0

Reorder the terms:
-3a + ab + (bs + -3s) = 0
-3a + ab + (bs + -3s) = 0

Solving
-3a + ab + bs + -3s = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-1bs' to each side of the equation.
-3a + ab + bs + -1bs + -3s = 0 + -1bs

Combine like terms: bs + -1bs = 0
-3a + ab + 0 + -3s = 0 + -1bs
-3a + ab + -3s = 0 + -1bs
Remove the zero:
-3a + ab + -3s = -1bs

Add '3s' to each side of the equation.
-3a + ab + -3s + 3s = -1bs + 3s

Combine like terms: -3s + 3s = 0
-3a + ab + 0 = -1bs + 3s
-3a + ab = -1bs + 3s

Reorder the terms:
-3a + ab + bs + -3s = -1bs + bs + 3s + -3s

Combine like terms: -1bs + bs = 0
-3a + ab + bs + -3s = 0 + 3s + -3s
-3a + ab + bs + -3s = 3s + -3s

Combine like terms: 3s + -3s = 0
-3a + ab + bs + -3s = 0

The solution to this equation could not be determined.

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