a(b+c)+2(b+c)=

Solution for a(b+c)+2(b+c)= equation:

Simplifying
a(b + c) + 2(b + c) = 0
(b * a + c * a) + 2(b + c) = 0
(ab + ac) + 2(b + c) = 0
ab + ac + (b * 2 + c * 2) = 0
ab + ac + (2b + 2c) = 0

Solving
ab + ac + 2b + 2c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-2b' to each side of the equation.
ab + ac + 2b + -2b + 2c = 0 + -2b

Combine like terms: 2b + -2b = 0
ab + ac + 0 + 2c = 0 + -2b
ab + ac + 2c = 0 + -2b
Remove the zero:
ab + ac + 2c = -2b

Add '-2c' to each side of the equation.
ab + ac + 2c + -2c = -2b + -2c

Combine like terms: 2c + -2c = 0
ab + ac + 0 = -2b + -2c
ab + ac = -2b + -2c

Reorder the terms:
ab + ac + 2b + 2c = -2b + 2b + -2c + 2c

Combine like terms: -2b + 2b = 0
ab + ac + 2b + 2c = 0 + -2c + 2c
ab + ac + 2b + 2c = -2c + 2c

Combine like terms: -2c + 2c = 0
ab + ac + 2b + 2c = 0

The solution to this equation could not be determined.