a(2b)+b(2c)+c=14

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Solution for a(2b)+b(2c)+c=14 equation:


Simplifying
a(2b) + b(2c) + c = 14

Remove parenthesis around (2b)
a * 2b + b(2c) + c = 14

Reorder the terms for easier multiplication:
2a * b + b(2c) + c = 14

Multiply a * b
2ab + b(2c) + c = 14

Remove parenthesis around (2c)
2ab + b * 2c + c = 14

Reorder the terms for easier multiplication:
2ab + 2b * c + c = 14

Multiply b * c
2ab + 2bc + c = 14

Solving
2ab + 2bc + c = 14

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-2bc' to each side of the equation.
2ab + 2bc + -2bc + c = 14 + -2bc

Combine like terms: 2bc + -2bc = 0
2ab + 0 + c = 14 + -2bc
2ab + c = 14 + -2bc

Add '-1c' to each side of the equation.
2ab + c + -1c = 14 + -2bc + -1c

Combine like terms: c + -1c = 0
2ab + 0 = 14 + -2bc + -1c
2ab = 14 + -2bc + -1c

Divide each side by '2b'.
a = 7b-1 + -1c + -0.5b-1c

Simplifying
a = 7b-1 + -1c + -0.5b-1c

Reorder the terms:
a = 7b-1 + -0.5b-1c + -1c

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