a(24-a)-128=0

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Solution for a(24-a)-128=0 equation:


Simplifying
a(24 + -1a) + -128 = 0
(24 * a + -1a * a) + -128 = 0
(24a + -1a2) + -128 = 0

Reorder the terms:
-128 + 24a + -1a2 = 0

Solving
-128 + 24a + -1a2 = 0

Solving for variable 'a'.

Factor a trinomial.
(-16 + a)(8 + -1a) = 0

Subproblem 1

Set the factor '(-16 + a)' equal to zero and attempt to solve: Simplifying -16 + a = 0 Solving -16 + a = 0 Move all terms containing a to the left, all other terms to the right. Add '16' to each side of the equation. -16 + 16 + a = 0 + 16 Combine like terms: -16 + 16 = 0 0 + a = 0 + 16 a = 0 + 16 Combine like terms: 0 + 16 = 16 a = 16 Simplifying a = 16

Subproblem 2

Set the factor '(8 + -1a)' equal to zero and attempt to solve: Simplifying 8 + -1a = 0 Solving 8 + -1a = 0 Move all terms containing a to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1a = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1a = 0 + -8 -1a = 0 + -8 Combine like terms: 0 + -8 = -8 -1a = -8 Divide each side by '-1'. a = 8 Simplifying a = 8

Solution

a = {16, 8}

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