Z=(63+16i)/(5+12i)

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Solution for Z=(63+16i)/(5+12i) equation:



=(63+16Z)/(5+12Z)
We move all terms to the left:
-((63+16Z)/(5+12Z))=0
Domain of the equation: (5+12Z))!=0
We move all terms containing Z to the left, all other terms to the right
12Z)!=-5
Z!=-5/1
Z!=-5
Z∈R
We add all the numbers together, and all the variables
-((16Z+63)/(12Z+5))=0
We multiply all the terms by the denominator
-((16Z+63)=0
We calculate terms in parentheses: -((16Z+63), so:
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We calculate terms in parentheses: -((16Z+63), so:
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We calculate terms in parentheses: -((16Z+63), so:
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