Z=(2k-45)/k

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Solution for Z=(2k-45)/k equation: 



=(2Z-45)/Z

We move all terms to the left:

-((2Z-45)/Z)=0



Domain of the equation: Z)!=0

Z!=0/1

Z!=0

Z∈R



We multiply all the terms by the denominator


-((2Z-45)=0



We calculate terms in parentheses: -((2Z-45), so:

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