Z-8(z+4)=-7(z+4)+-3

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Solution for Z-8(z+4)=-7(z+4)+-3 equation: 



-8(Z+4)=-7(Z+4)+-3

We move all terms to the left:

-8(Z+4)-(-7(Z+4)+-3)=0

We use the square of the difference formula

-8(Z+4)-(-7(Z+4)-3)=0

We multiply parentheses

-8Z-(-7(Z+4)-3)-32=0



We calculate terms in parentheses: -(-7(Z+4)-3), so:

-7(Z+4)-3

We multiply parentheses

-7Z-28-3

We add all the numbers together, and all the variables

-7Z-31

Back to the equation:

-(-7Z-31)



We get rid of parentheses

-8Z+7Z+31-32=0

We add all the numbers together, and all the variables

-1Z-1=0

We move all terms containing Z to the left, all other terms to the right

-Z=1

Z=1/-1

Z=-1

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