Z-(2+11i)=(3+7i)

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Solution for Z-(2+11i)=(3+7i) equation: 



-(2+11Z)=(3+7Z)

We move all terms to the left:

-(2+11Z)-((3+7Z))=0

We add all the numbers together, and all the variables

-(11Z+2)-((7Z+3))=0

We get rid of parentheses

-11Z-((7Z+3))-2=0



We calculate terms in parentheses: -((7Z+3)), so:

(7Z+3)

We get rid of parentheses

7Z+3

Back to the equation:

-(7Z+3)



We get rid of parentheses

-11Z-7Z-3-2=0

We add all the numbers together, and all the variables

-18Z-5=0

We move all terms containing Z to the left, all other terms to the right

-18Z=5

Z=5/-18

Z=-5/18

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