Z+3(2+4z)=6(2+1)+5z

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Solution for Z+3(2+4z)=6(2+1)+5z equation: 



+3(2+4Z)=6(2+1)+5Z

We move all terms to the left:

+3(2+4Z)-(6(2+1)+5Z)=0

We add all the numbers together, and all the variables

3(4Z+2)-(63+5Z)=0

We multiply parentheses

12Z-(63+5Z)+6=0

We get rid of parentheses

12Z-5Z-63+6=0

We add all the numbers together, and all the variables

7Z-57=0

We move all terms containing Z to the left, all other terms to the right

7Z=57

Z=57/7

Z=8+1/7

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