Z(a+3)=3(a-15)

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Solution for Z(a+3)=3(a-15) equation: 



(Z+3)=3(Z-15)

We move all terms to the left:

(Z+3)-(3(Z-15))=0

We get rid of parentheses

Z-(3(Z-15))+3=0



We calculate terms in parentheses: -(3(Z-15)), so:

3(Z-15)

We multiply parentheses

3Z-45

Back to the equation:

-(3Z-45)



We get rid of parentheses

Z-3Z+45+3=0

We add all the numbers together, and all the variables

-2Z+48=0

We move all terms containing Z to the left, all other terms to the right

-2Z=-48

Z=-48/-2

Z=+24

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