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=Y2+Y-2
We move all terms to the left:
-(Y2+Y-2)=0
We add all the numbers together, and all the variables
-(+Y^2+Y-2)=0
We get rid of parentheses
-Y^2-Y+2=0
We add all the numbers together, and all the variables
-1Y^2-1Y+2=0
a = -1; b = -1; c = +2;
Δ = b2-4ac
Δ = -12-4·(-1)·2
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-3}{2*-1}=\frac{-2}{-2} =1 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+3}{2*-1}=\frac{4}{-2} =-2 $
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