Y=x2+4x+12

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Solution for Y=x2+4x+12 equation: 



=Y2+4Y+12

We move all terms to the left:

-(Y2+4Y+12)=0

We add all the numbers together, and all the variables

-(+Y^2+4Y+12)=0

We get rid of parentheses

-Y^2-4Y-12=0

We add all the numbers together, and all the variables

-1Y^2-4Y-12=0

a = -1; b = -4; c = -12;
Δ = b2-4ac
Δ = -42-4·(-1)·(-12)
Δ = -32
Delta is less than zero, so there is no solution for the equation

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