Y=x2+3x-5

Solution for Y=x2+3x-5 equation:

=Y2+3Y-5

We move all terms to the left:

-(Y2+3Y-5)=0

We add all the numbers together, and all the variables

-(+Y^2+3Y-5)=0

We get rid of parentheses

-Y^2-3Y+5=0

We add all the numbers together, and all the variables

-1Y^2-3Y+5=0

a = -1; b = -3; c = +5;
Δ = b2-4ac
Δ = -32-4·(-1)·5
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{29}}{2*-1}=\frac{3-\sqrt{29}}{-2}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{29}}{2*-1}=\frac{3+\sqrt{29}}{-2}
$