Y=8x2-18x

Solution for Y=8x2-18x equation:

=8Y^2-18Y

We move all terms to the left:

-(8Y^2-18Y)=0

We get rid of parentheses

-8Y^2+18Y=0

a = -8; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·(-8)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*-8}=\frac{-36}{-16}
=2+1/4
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*-8}=\frac{0}{-16}
=0
$