Y=4(x-6)+2(3x-5)

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Solution for Y=4(x-6)+2(3x-5) equation: 



=4(Y-6)+2(3Y-5)

We move all terms to the left:

-(4(Y-6)+2(3Y-5))=0



We calculate terms in parentheses: -(4(Y-6)+2(3Y-5)), so:

4(Y-6)+2(3Y-5)

We multiply parentheses

4Y+6Y-24-10

We add all the numbers together, and all the variables

10Y-34

Back to the equation:

-(10Y-34)



We get rid of parentheses

-10Y+34=0

We move all terms containing Y to the left, all other terms to the right

-10Y=-34

Y=-34/-10

Y=3+2/5

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