Y=2/3(y-2)

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Solution for Y=2/3(y-2) equation: 


x in (-oo:+oo)

Y = (2/3)*(y-2) // - (2/3)*(y-2)

Y-((2/3)*(y-2)) = 0

(-2/3)*(y-2)+Y = 0

Y-2/3*(y-2) = 0

Y-2/3*(y-2) = 0

Y-2/3*y+4/3 = 0

Y-2/3*y+4/3 = 0

x belongs to the empty set

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