Y=2(-3y-5)+10

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Solution for Y=2(-3y-5)+10 equation: 



=2(-3Y-5)+10

We move all terms to the left:

-(2(-3Y-5)+10)=0



We calculate terms in parentheses: -(2(-3Y-5)+10), so:

2(-3Y-5)+10

We multiply parentheses

-6Y-10+10

We add all the numbers together, and all the variables

-6Y

Back to the equation:

-(-6Y)



We get rid of parentheses

6Y=0

Y=0/6

Y=0

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