Y=12x-8(x-4)+2

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Solution for Y=12x-8(x-4)+2 equation: 



=12Y-8(Y-4)+2

We move all terms to the left:

-(12Y-8(Y-4)+2)=0



We calculate terms in parentheses: -(12Y-8(Y-4)+2), so:

12Y-8(Y-4)+2

We multiply parentheses

12Y-8Y+32+2

We add all the numbers together, and all the variables

4Y+34

Back to the equation:

-(4Y+34)



We get rid of parentheses

-4Y-34=0

We move all terms containing Y to the left, all other terms to the right

-4Y=34

Y=34/-4

Y=-8+1/2

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