Y=11x2-5

Solution for Y=11x2-5 equation:

=11Y^2-5

We move all terms to the left:

-(11Y^2-5)=0

We get rid of parentheses

-11Y^2+5=0

a = -11; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-11)·5
Δ = 220
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{220}=\sqrt{4*55}=\sqrt{4}*\sqrt{55}=2\sqrt{55}$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{55}}{2*-11}=\frac{0-2\sqrt{55}}{-22}
=-\frac{2\sqrt{55}}{-22}
=-\frac{\sqrt{55}}{-11}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{55}}{2*-11}=\frac{0+2\sqrt{55}}{-22}
=\frac{2\sqrt{55}}{-22}
=\frac{\sqrt{55}}{-11}
$