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=-4.9Y^2+12.25Y
We move all terms to the left:
-(-4.9Y^2+12.25Y)=0
We get rid of parentheses
4.9Y^2-12.25Y=0
a = 4.9; b = -12.25; c = 0;
Δ = b2-4ac
Δ = -12.252-4·4.9·0
Δ = 150.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12.25)-\sqrt{150.0625}}{2*4.9}=\frac{12.25-\sqrt{150.0625}}{9.8} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12.25)+\sqrt{150.0625}}{2*4.9}=\frac{12.25+\sqrt{150.0625}}{9.8} $
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