Y=-3(x-4)+5(2x-1)

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Solution for Y=-3(x-4)+5(2x-1) equation: 



=-3(Y-4)+5(2Y-1)

We move all terms to the left:

-(-3(Y-4)+5(2Y-1))=0



We calculate terms in parentheses: -(-3(Y-4)+5(2Y-1)), so:

-3(Y-4)+5(2Y-1)

We multiply parentheses

-3Y+10Y+12-5

We add all the numbers together, and all the variables

7Y+7

Back to the equation:

-(7Y+7)



We get rid of parentheses

-7Y-7=0

We move all terms containing Y to the left, all other terms to the right

-7Y=7

Y=7/-7

Y=-1

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