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=-16Y(Y-2)
We move all terms to the left:
-(-16Y(Y-2))=0
We calculate terms in parentheses: -(-16Y(Y-2)), so:We get rid of parentheses
-16Y(Y-2)
We multiply parentheses
-16Y^2+32Y
Back to the equation:
-(-16Y^2+32Y)
16Y^2-32Y=0
a = 16; b = -32; c = 0;
Δ = b2-4ac
Δ = -322-4·16·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-32}{2*16}=\frac{0}{32} =0 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+32}{2*16}=\frac{64}{32} =2 $
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