Y=(x-60)(2x+130)

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Solution for Y=(x-60)(2x+130) equation:



=(Y-60)(2Y+130)
We move all terms to the left:
-((Y-60)(2Y+130))=0
We multiply parentheses ..
-((+2Y^2+130Y-120Y-7800))=0
We calculate terms in parentheses: -((+2Y^2+130Y-120Y-7800)), so:
(+2Y^2+130Y-120Y-7800)
We get rid of parentheses
2Y^2+130Y-120Y-7800
We add all the numbers together, and all the variables
2Y^2+10Y-7800
Back to the equation:
-(2Y^2+10Y-7800)
We get rid of parentheses
-2Y^2-10Y+7800=0
a = -2; b = -10; c = +7800;
Δ = b2-4ac
Δ = -102-4·(-2)·7800
Δ = 62500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{62500}=250$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-250}{2*-2}=\frac{-240}{-4} =+60 $
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+250}{2*-2}=\frac{260}{-4} =-65 $

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