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=(7Y-1)(6Y-1)
We move all terms to the left:
-((7Y-1)(6Y-1))=0
We multiply parentheses ..
-((+42Y^2-7Y-6Y+1))=0
We calculate terms in parentheses: -((+42Y^2-7Y-6Y+1)), so:We get rid of parentheses
(+42Y^2-7Y-6Y+1)
We get rid of parentheses
42Y^2-7Y-6Y+1
We add all the numbers together, and all the variables
42Y^2-13Y+1
Back to the equation:
-(42Y^2-13Y+1)
-42Y^2+13Y-1=0
a = -42; b = 13; c = -1;
Δ = b2-4ac
Δ = 132-4·(-42)·(-1)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-1}{2*-42}=\frac{-14}{-84} =1/6 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+1}{2*-42}=\frac{-12}{-84} =1/7 $
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