Y=(36-2x)x

Solution for Y=(36-2x)x equation:

=(36-2Y)Y

We move all terms to the left:

-((36-2Y)Y)=0

We add all the numbers together, and all the variables

-((-2Y+36)Y)=0


We calculate terms in parentheses: -((-2Y+36)Y), so:

(-2Y+36)Y

We multiply parentheses

-2Y^2+36Y

Back to the equation:

-(-2Y^2+36Y)


We get rid of parentheses

2Y^2-36Y=0

a = 2; b = -36; c = 0;
Δ = b2-4ac
Δ = -362-4·2·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-36}{2*2}=\frac{0}{4}
=0
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+36}{2*2}=\frac{72}{4}
=18
$