Y=(2x-5)/(x+3)

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Solution for Y=(2x-5)/(x+3) equation:



=(2Y-5)/(Y+3)
We move all terms to the left:
-((2Y-5)/(Y+3))=0
Domain of the equation: (Y+3))!=0
Y∈R
We multiply all the terms by the denominator
-((2Y-5)=0
We calculate terms in parentheses: -((2Y-5), so:
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We calculate terms in parentheses: -((2Y-5), so:
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We calculate terms in parentheses: -((2Y-5), so:
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We calculate terms in parentheses: -((2Y-5), so:
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We calculate terms in parentheses: -((2Y-5), so:
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We calculate terms in parentheses: -((2Y-5), so:
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We calculate terms in parentheses: -((2Y-5), so:
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We calculate terms in parentheses: -((2Y-5), so:
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We calculate terms in parentheses: -((2Y-5), so:
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We calculate terms in parentheses: -((2Y-5), so:
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We calculate terms in parentheses: -((2Y-5), so:
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We calculate terms in parentheses: -((2Y-5), so:
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We calculate terms in parentheses: -((2Y-5), so:
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We calculate terms in parentheses: -((2Y-5), so:
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We calculate terms in parentheses: -((2Y-5), so:
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We calculate terms in parentheses: -((2Y-5), so:
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We calculate terms in parentheses: -((2Y-5), so:
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We calculate terms in parentheses: -((2Y-5), so:
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We calculate terms in parentheses: -((2Y-5), so:
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We calculate terms in parentheses: -((2Y-5), so:
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