Y4(2+3c)=56

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Solution for Y4(2+3c)=56 equation: 



4(2+3Y)=56

We move all terms to the left:

4(2+3Y)-(56)=0

We add all the numbers together, and all the variables

4(3Y+2)-56=0

We multiply parentheses

12Y+8-56=0

We add all the numbers together, and all the variables

12Y-48=0

We move all terms containing Y to the left, all other terms to the right

12Y=48

Y=48/12

Y=4

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