Y3-y2-21y+45=0

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Solution for Y3-y2-21y+45=0 equation:



3-Y2-21Y+45=0
We add all the numbers together, and all the variables
-1Y^2-21Y+48=0
a = -1; b = -21; c = +48;
Δ = b2-4ac
Δ = -212-4·(-1)·48
Δ = 633
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{633}}{2*-1}=\frac{21-\sqrt{633}}{-2} $
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{633}}{2*-1}=\frac{21+\sqrt{633}}{-2} $

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