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2+Y2+8Y=84
We move all terms to the left:
2+Y2+8Y-(84)=0
We add all the numbers together, and all the variables
Y^2+8Y-82=0
a = 1; b = 8; c = -82;
Δ = b2-4ac
Δ = 82-4·1·(-82)
Δ = 392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{392}=\sqrt{196*2}=\sqrt{196}*\sqrt{2}=14\sqrt{2}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-14\sqrt{2}}{2*1}=\frac{-8-14\sqrt{2}}{2} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+14\sqrt{2}}{2*1}=\frac{-8+14\sqrt{2}}{2} $
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