Y-5=3/4(x+12)

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Solution for Y-5=3/4(x+12) equation:



-5=3/4(Y+12)
We move all terms to the left:
-5-(3/4(Y+12))=0
Domain of the equation: 4(Y+12))!=0
Y∈R
We multiply all the terms by the denominator
-(3-5*4(Y+12))=0
We calculate terms in parentheses: -(3-5*4(Y+12)), so:
3-5*4(Y+12)
determiningTheFunctionDomain -5*4(Y+12)+3
Wy multiply elements
-20Y(Y+3
Back to the equation:
-(-20Y(Y+3)
We calculate terms in parentheses: -(-20Y(Y+3), so:
-20Y(Y+3
We calculate terms in parentheses: -(-20Y(Y+3), so:
-20Y(Y+3
We calculate terms in parentheses: -(-20Y(Y+3), so:
-20Y(Y+3
We calculate terms in parentheses: -(-20Y(Y+3), so:
-20Y(Y+3
We calculate terms in parentheses: -(-20Y(Y+3), so:
-20Y(Y+3
We calculate terms in parentheses: -(-20Y(Y+3), so:
-20Y(Y+3
We calculate terms in parentheses: -(-20Y(Y+3), so:
-20Y(Y+3
We calculate terms in parentheses: -(-20Y(Y+3), so:
-20Y(Y+3
We calculate terms in parentheses: -(-20Y(Y+3), so:
-20Y(Y+3
We calculate terms in parentheses: -(-20Y(Y+3), so:
-20Y(Y+3
We calculate terms in parentheses: -(-20Y(Y+3), so:
-20Y(Y+3
We calculate terms in parentheses: -(-20Y(Y+3), so:
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We calculate terms in parentheses: -(-20Y(Y+3), so:
-20Y(Y+3
We calculate terms in parentheses: -(-20Y(Y+3), so:
-20Y(Y+3
We calculate terms in parentheses: -(-20Y(Y+3), so:
-20Y(Y+3
We calculate terms in parentheses: -(-20Y(Y+3), so:
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