Y-5=3/2(x+4)

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Solution for Y-5=3/2(x+4) equation: 



-5=3/2(Y+4)

We move all terms to the left:

-5-(3/2(Y+4))=0



Domain of the equation: 2(Y+4))!=0

Y∈R



We multiply all the terms by the denominator


-(3-5*2(Y+4))=0



We calculate terms in parentheses: -(3-5*2(Y+4)), so:

3-5*2(Y+4)

determiningTheFunctionDomain
-5*2(Y+4)+3

Wy multiply elements

-10Y(Y+3

Back to the equation:

-(-10Y(Y+3)





We calculate terms in parentheses: -(-10Y(Y+3), so:

-10Y(Y+3





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-10Y(Y+3





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-10Y(Y+3





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-10Y(Y+3





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-10Y(Y+3





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-10Y(Y+3





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-10Y(Y+3





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-10Y(Y+3





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-10Y(Y+3





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-10Y(Y+3





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-10Y(Y+3





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-10Y(Y+3





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