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-5=1/2(Y+4)
We move all terms to the left:
-5-(1/2(Y+4))=0
Domain of the equation: 2(Y+4))!=0We multiply all the terms by the denominator
Y∈R
-(1-5*2(Y+4))=0
We calculate terms in parentheses: -(1-5*2(Y+4)), so:
1-5*2(Y+4)
determiningTheFunctionDomain -5*2(Y+4)+1
Wy multiply elements
-10Y(Y+1
Back to the equation:
-(-10Y(Y+1)
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| -7x-8=3(x+4) | | 13+x2x+12=x+32 | | 2/u-3=3/5 | | -3x+4-x=12 | | 23=w+11 | | -5x-8x=10 | | 165=20-x | | 3x+5+84=6x+7 | | -4(x-7)=2x-8 | | 6+12x=14x-18 | | -5x+4(x-3)=-23-x+11 | | 5(r+9)-2(1+4)=1 | | 2q+5=-5+3q | | 7(5x-10)=-140 | | 141=9.5x+65 | | -6d=-6d-6 | | 9-2u=-2u | | -10t=-5t+10 | | 10k=+7=-3+10k | | 9y-2-5y=14 | | 3b+20=20 | | -x/4=-51 | | 4u-24=6u-8 | | 4u+24=6u-8 | | 4u+24=6u-6 | | 8y-40-18y=-y | | 4x8-3=92 | | 11(k-1)=7(k-70) | | 4y-4-y+5=10 | | 6p+32-p=22 | | (1/x-5)-(2/x+8)=(13/(x-5)(x+8) | | (X-5)/3=(x+4)/9 |