Y-4+2(4y+4)=-6(y+1)

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Solution for Y-4+2(4y+4)=-6(y+1) equation: 



-4+2(4Y+4)=-6(Y+1)

We move all terms to the left:

-4+2(4Y+4)-(-6(Y+1))=0

We multiply parentheses

8Y-(-6(Y+1))+8-4=0



We calculate terms in parentheses: -(-6(Y+1)), so:

-6(Y+1)

We multiply parentheses

-6Y-6

Back to the equation:

-(-6Y-6)



We add all the numbers together, and all the variables

8Y-(-6Y-6)+4=0

We get rid of parentheses

8Y+6Y+6+4=0

We add all the numbers together, and all the variables

14Y+10=0

We move all terms containing Y to the left, all other terms to the right

14Y=-10

Y=-10/14

Y=-5/7

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