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x in (-oo:+oo)
Y-((1/5)*(2-(5*y))) = -(5*y)-37/5 // + -(5*y)-37/5
Y-((1/5)*(2-(5*y)))+5*y-(-37/5) = 0
(-1/5)*(2-5*y)+Y+5*y+37/5 = 0
Y-1/5*(2-5*y)+5*y+37/5 = 0
(-1/5*5*(2-5*y))/5+(5*Y)/5+(5*5*y)/5+37/5 = 0
5*Y-1/5*5*(2-5*y)+5*5*y+37 = 0
5*Y+5*y+25*y-2+37 = 0
5*Y+30*y-2+37 = 0
5*Y+30*y+35 = 0
(5*Y+30*y+35)/5 = 0
(5*Y+30*y+35)/5 = 0 // * 5
5*Y+30*y+35 = 0
x belongs to the empty set
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